PhysicsEquilibrium of forcesWAEC
A uniform metre rule balances at its 50 cm mark. A 30 g mass hangs at the 20 cm mark. Where must a 20 g mass hang to restore balance?
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Answer: B. 95 cm mark
Moments: 30 × (50 − 20) = 20 × d, so d = 45 cm from the pivot, at the 95 cm mark.
An AdmitMe practice question, written for the WAEC syllabus. Not an official past question.