PhysicsEquilibrium of forcesJAMB
A uniform metre rule of weight 2 N is pivoted at the 30 cm mark. What weight hung at the 10 cm mark will keep it horizontal?
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Answer: B. 2 N
The rule's weight acts at 50 cm, 20 cm from the pivot: 2 × 20 = W × 20, so W = 2 N.
An AdmitMe practice question, written for the JAMB syllabus. Not an official past question.