PhysicsEquilibrium of forcesWAEC
A see-saw pivoted at its centre has a 400 N child 1.5 m from the pivot. How far on the other side must a 300 N child sit to balance?
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Answer: B. 2.0 m
400 × 1.5 = 300 × d, so d = 2 m.
An AdmitMe practice question, written for the WAEC syllabus. Not an official past question.