MathematicsDifferentiationJAMB
Find the minimum value of y = x² − 4x + 7.
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Answer: A. 3
dy/dx = 2x − 4 = 0 at x = 2, so y = 4 − 8 + 7 = 3.
An AdmitMe practice question, written for the JAMB syllabus. Not an official past question.
MathematicsDifferentiationJAMB
Answer: A. 3
dy/dx = 2x − 4 = 0 at x = 2, so y = 4 − 8 + 7 = 3.
An AdmitMe practice question, written for the JAMB syllabus. Not an official past question.
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