MathematicsDifferentiationJAMB
Find the minimum point of the curve y = 2x² − 8x + 3.
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Answer: B. (2, −5)
dy/dx = 4x − 8 = 0 gives x = 2; y = 8 − 16 + 3 = −5.
An AdmitMe practice question, written for the JAMB syllabus. Not an official past question.