PhysicsSimple a.c. circuitsWAEC
The peak value of an alternating current is 10√2 A. Find its r.m.s. value.
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Answer: C. 10 A
I(rms) = I(peak)/√2 = 10√2/√2 = 10 A.
An AdmitMe practice question, written for the WAEC syllabus. Not an official past question.