PhysicsElementary modern physicsJAMB
In the decay ²³⁸₉₂U → ²³⁴₉₀Th + X, the particle X is
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Answer: D. an alpha particle
Mass number falls by 4 and atomic number by 2, which is the emission of a helium nucleus (alpha particle).
An AdmitMe practice question, written for the JAMB syllabus. Not an official past question.