PhysicsCapacitorsJAMB
Find the energy stored in a 4 μF capacitor charged to 100 V.
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Answer: B. 0.02 J
E = ½CV² = ½ × 4 × 10⁻⁶ × 100² = 0.02 J.
An AdmitMe practice question, written for the JAMB syllabus. Not an official past question.
Physics · Capacitors
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