PhysicsCurrent electricityWAEC
Find the combined resistance of 4 Ω and 12 Ω resistors connected in parallel.
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Answer: B. 3 Ω
R = (4 × 12)/(4 + 12) = 48/16 = 3 Ω.
An AdmitMe practice question, written for the WAEC syllabus. Not an official past question.