PhysicsSimple a.c. circuitsJAMB
An alternating voltage has a peak value of 10√2 V. Find its r.m.s. value.
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Answer: D. 10 V
V(rms) = V(peak)/√2 = 10√2/√2 = 10 V.
An AdmitMe practice question, written for the JAMB syllabus. Not an official past question.