PhysicsSimple a.c. circuitsWAEC
An alternating current has a peak value of 10√2 A. Its r.m.s. value is
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Answer: A. 10 A
I r.m.s. = I₀/√2 = 10√2/√2 = 10 A.
An AdmitMe practice question, written for the WAEC syllabus. Not an official past question.