PhysicsElectric cellsJAMB
A cell of e.m.f. 3 V and internal resistance 1 Ω drives a current through a 5 Ω resistor. Find the terminal potential difference of the cell.
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Answer: B. 2.5 V
I = 3/6 = 0.5 A; terminal p.d. = IR = 0.5 × 5 = 2.5 V (0.5 V is lost inside the cell).
An AdmitMe practice question, written for the JAMB syllabus. Not an official past question.