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PhysicsCapacitorsWAEC

A capacitor stores a charge of 0.002 C at 50 V. Find its capacitance.

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Answer: C. 4 × 10⁻⁵ F

C = Q/V = 0.002/50 = 4 × 10⁻⁵ F.

An AdmitMe practice question, written for the WAEC syllabus. Not an official past question.

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