PhysicsMotionJAMB
A body moving with velocity 30 m/s decelerates uniformly at 5 m/s². The distance covered before coming to rest is:
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Answer: A. 90 m
v² = u² − 2as → 0 = 900 − 10s → s = 90 m.
An AdmitMe practice question, written for the JAMB syllabus. Not an official past question.