PhysicsElectric cellsWAEC
A battery of e.m.f. 12 V and internal resistance 2 Ω drives current through a 10 Ω lamp. Find the terminal p.d.
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Answer: A. 10 V
I = 12/(10 + 2) = 1 A, so the terminal p.d. = IR = 1 × 10 = 10 V.
An AdmitMe practice question, written for the WAEC syllabus. Not an official past question.