JAMB and WAEC Mathematics questions

861 questions with answers and explanations. Tap an option to check yourself.

All JAMB WAEC

Question 481· Number bases· JAMB
Express 45 (base 10) in base 3.
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Answer: A. 1200
Explanation and discussion
Question 482· Number bases· JAMB
Convert 1011 (base 2) to base 10.
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Answer: B. 11
Explanation and discussion
Question 483· Number bases· JAMB
Express 100 (base 10) in base 5.
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Answer: B. 400
Explanation and discussion
Question 484· Number bases· JAMB
If 23 (base x) = 11 (base 10), find x.
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Answer: A. 4
Explanation and discussion
Question 485· Number bases· WAEC
Convert 213 in base four to base ten.
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Answer: B. 39
Explanation and discussion
Question 486· Number bases· WAEC
Multiply 11₂ by 101₂, giving the answer in base two.
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Answer: B. 1111
Explanation and discussion
Question 487· Number bases· JAMB
Find x if 132ₓ = 42 (base ten).
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Answer: B. 5
Explanation and discussion
Question 488· Number bases· WAEC
Express 213₄ as a number in base ten.
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Answer: D. 39
Explanation and discussion
Question 489· Number bases· JAMB
Convert 0.75 (base 10) to base 2.
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Answer: C. 0.11
Explanation and discussion
Question 490· Number bases· WAEC
Add 1101₂ and 1011₂, giving the answer in base two.
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Answer: A. 11000
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Question 491· Number bases· JAMB
Convert 432 (base 5) to base 10.
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Answer: A. 117
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Question 492· Number bases· WAEC
Find the value of x if 23ₓ = 17 (base ten).
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Answer: B. 7
Explanation and discussion
Question 493· Number bases· WAEC
Express 87 (base ten) in base five.
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Answer: A. 322₅
Explanation and discussion
Question 494· Permutation and combination· JAMB
In how many ways can the letters of the word BANANA be arranged?
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Answer: B. 60
Explanation and discussion
Question 495· Permutation and combination· JAMB
In how many ways can 4 different books be arranged on a shelf?
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Answer: A. 24
Explanation and discussion
Question 496· Permutation and combination· JAMB
How many different 3-letter arrangements can be made from the letters of the word MATHS, without repetition?
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Answer: C. 60
Explanation and discussion
Question 497· Permutation and combination· JAMB
In how many ways can 3 students be chosen from 7?
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Answer: A. 35
Explanation and discussion
Question 498· Permutation and combination· JAMB
In how many ways can a chairman and a secretary be chosen from 7 members?
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Answer: C. 42
Explanation and discussion
Question 499· Permutation and combination· JAMB
A committee of 4 with exactly 2 women is chosen from 6 men and 4 women. In how many ways can this be done?
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Answer: B. 90
Explanation and discussion
Question 500· Permutation and combination· JAMB
In how many ways can 2 prefects be chosen from 10 students (that is, ¹⁰C₂)?
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Answer: D. 45
Explanation and discussion

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JAMB and WAEC Mathematics questions

Express 45 (base 10) in base 3.

Convert 1011 (base 2) to base 10.

Express 100 (base 10) in base 5.

If 23 (base x) = 11 (base 10), find x.

Convert 213 in base four to base ten.

Multiply 11₂ by 101₂, giving the answer in base two.

Find x if 132ₓ = 42 (base ten).

Express 213₄ as a number in base ten.

Convert 0.75 (base 10) to base 2.

Add 1101₂ and 1011₂, giving the answer in base two.

Convert 432 (base 5) to base 10.

Find the value of x if 23ₓ = 17 (base ten).

Express 87 (base ten) in base five.

In how many ways can the letters of the word BANANA be arranged?

In how many ways can 4 different books be arranged on a shelf?

How many different 3-letter arrangements can be made from the letters of the word MATHS, without repetition?

In how many ways can 3 students be chosen from 7?

In how many ways can a chairman and a secretary be chosen from 7 members?

A committee of 4 with exactly 2 women is chosen from 6 men and 4 women. In how many ways can this be done?

In how many ways can 2 prefects be chosen from 10 students (that is, ¹⁰C₂)?