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y varies directly as x². If y = 12 when x = 2, find y when x = 3.

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Answer: C. 27

y = kx²: 12 = 4k, so k = 3; when x = 3, y = 3 × 9 = 27.

An AdmitMe practice question, written for the JAMB syllabus. Not an official past question.

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