MathematicsPermutation and combinationJAMB
A team of 3 is to be chosen from 5 boys and 4 girls. In how many ways can this be done if the team must include at least one girl?
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Answer: B. 74
All teams: ⁹C₃ = 84; teams with no girl: ⁵C₃ = 10; 84 − 10 = 74.
An AdmitMe practice question, written for the JAMB syllabus. Not an official past question.