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A box contains 5 red and 3 blue balls. Two balls are drawn at random without replacement. Find the probability that one is red and one is blue.

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Answer: B. 15/28

Red then blue: 5/8 × 3/7 = 15/56; blue then red gives the same, so 30/56 = 15/28.

An AdmitMe practice question, written for the JAMB syllabus. Not an official past question.

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