Further MathematicsDifferentiationWAEC
Find the maximum value of y = 6x − x².
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Answer: A. 9
dy/dx = 6 − 2x = 0 at x = 3, giving y = 18 − 9 = 9.
An AdmitMe practice question, written for the WAEC syllabus. Not an official past question.
Further MathematicsDifferentiationWAEC
Answer: A. 9
dy/dx = 6 − 2x = 0 at x = 3, giving y = 18 − 9 = 9.
An AdmitMe practice question, written for the WAEC syllabus. Not an official past question.
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