Further MathematicsIntegrationWAEC
A particle moves with velocity v = 3t² + 2 m/s. Find the distance it covers from t = 0 to t = 2 s.
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Answer: C. 12 m
s = [t³ + 2t] from 0 to 2 = 8 + 4 = 12 m.
An AdmitMe practice question, written for the WAEC syllabus. Not an official past question.