ChemistryAcids, bases and saltsJAMB
What volume of 0.2 mol/dm³ NaOH neutralises 20 cm³ of 0.1 mol/dm³ H₂SO₄?
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Answer: A. 20 cm³
H₂SO₄ + 2NaOH: moles of acid = 0.002, so NaOH = 0.004 mol; volume = 0.004/0.2 = 0.02 dm³ = 20 cm³.
An AdmitMe practice question, written for the JAMB syllabus. Not an official past question.