ChemistryChemical combinationJAMB
What volume of 0.1 mol/dm³ hydrochloric acid is needed to make 250 cm³ of 0.02 mol/dm³ acid?
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Answer: D. 50 cm³
C₁V₁ = C₂V₂: 0.1 × V = 0.02 × 250, so V = 50 cm³.
An AdmitMe practice question, written for the JAMB syllabus. Not an official past question.