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Chemistry · Oxidation and reduction

ChemistryOxidation and reductionWAEC

The oxidation number of chromium in K₂Cr₂O₇ is

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Answer: C. +6

2(+1) + 2Cr + 7(−2) = 0, so Cr = +6.

An AdmitMe practice question, written for the WAEC syllabus. Not an official past question.

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