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ChemistryChemical combinationJAMB

How many molecules are in 4.4 g of carbon(IV) oxide? [C = 12, O = 16, L = 6.0 × 10²³]

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Answer: D. 6.0 × 10²²

4.4/44 = 0.1 mol; 0.1 × 6.0 × 10²³ = 6.0 × 10²².

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