ChemistryChemical combinationWAEC
How many atoms are present in 0.5 mol of sulphur? [L = 6.02 × 10²³]
Show answer
Answer: B. 3.01 × 10²³
Number = 0.5 × 6.02 × 10²³ = 3.01 × 10²³.
An AdmitMe practice question, written for the WAEC syllabus. Not an official past question.