ChemistryAcids, bases and saltsJAMB
25 cm³ of 0.1 mol/dm³ NaOH neutralises 20 cm³ of HCl. The concentration of the acid is:
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Answer: A. 0.125 mol/dm³
Moles NaOH = 0.1 × 0.025 = 0.0025 = moles HCl (1:1); concentration = 0.0025/0.020 = 0.125 mol/dm³.
An AdmitMe practice question, written for the JAMB syllabus. Not an official past question.