ChemistryChemical combinationJAMB
0.5 g of a gas occupies 280 cm³ at s.t.p. Find its molar mass. [molar volume = 22.4 dm³]
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Answer: B. 40 g/mol
Moles = 0.28/22.4 = 0.0125; M = 0.5/0.0125 = 40 g/mol.
An AdmitMe practice question, written for the JAMB syllabus. Not an official past question.