PhysicsCurrent electricityWAEC
Two resistors of 4 Ω and 12 Ω are connected in parallel. Their combined resistance is
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Answer: A. 3 Ω
R = (4 × 12)/(4 + 12) = 48/16 = 3 Ω.
An AdmitMe practice question, written for the WAEC syllabus. Not an official past question.