PhysicsElectric cellsJAMB
Two cells, each of e.m.f. 1.5 V and internal resistance 0.5 Ω, are connected in series with a 4 Ω resistor. Find the current.
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Answer: C. 0.6 A
Total e.m.f. = 3 V; total resistance = 4 + 0.5 + 0.5 = 5 Ω; I = 3/5 = 0.6 A.
An AdmitMe practice question, written for the JAMB syllabus. Not an official past question.