Further MathematicsDynamicsWAEC
A particle is projected at 20 m/s at 45° to the horizontal. Find its horizontal range. [g = 10 m/s²]
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Answer: D. 40 m
R = u² sin 2θ/g = 400 × 1/10 = 40 m.
An AdmitMe practice question, written for the WAEC syllabus. Not an official past question.